How many of the following hydroxides is/are amphoteric in character?
CsOH , LiOH , `Ca(OH)_(2) , Be(OH)_(2) , Mg(OH)_(2) , Ba(OH)_(2) , Sr(OH)_(2) , Ba(OH)_(2) , KOH , NaOH`.

Explanation

To determine how many of the given hydroxides are amphoteric in character, we need to analyze each hydroxide listed in the question. Amphoteric hydroxides are those that can react with both acids and bases.

Here are the hydroxides we need to evaluate:

1. CsOH (Cesium hydroxide)
2. LiOH (Lithium hydroxide)
3. Ca(OH)₂ (Calcium hydroxide)
4. Be(OH)₂ (Beryllium hydroxide)
5. Mg(OH)₂ (Magnesium hydroxide)
6. Ba(OH)₂ (Barium hydroxide)
7. Sr(OH)₂ (Strontium hydroxide)
8. KOH (Potassium hydroxide)
9. NaOH (Sodium hydroxide)

### Step-by-Step Solution:

1. **Identify the Nature of Each Hydroxide**:
- **CsOH, LiOH, KOH, NaOH, Ca(OH)₂, Ba(OH)₂, Sr(OH)₂**: These are strong bases and primarily exhibit basic characteristics. They react with acids but not with bases.
- **Be(OH)₂**: This is a notable exception. Beryllium hydroxide is amphoteric; it can react with both acids and bases.

2. **Reactions of Beryllium Hydroxide**:
- When beryllium hydroxide reacts with an acid (e.g., hydrochloric acid), it forms beryllium chloride and water:
\[ \text{Be(OH)}_2 + 2 \text{HCl} \rightarrow \text{BeCl}_2 + 2 \text{H}_2\text{O} \]
- When beryllium hydroxide reacts with a strong base (e.g., sodium hydroxide), it forms a complex:
\[ \text{Be(OH)}_2 + 2 \text{NaOH} \rightarrow \text{Na}_2\text{Be(OH)}_4 \]

3. **Conclusion**:
- Among the listed hydroxides, only **Be(OH)₂** is amphoteric. The others are strong bases and do not exhibit amphoteric behavior.

### Final Answer:
Only **1** hydroxide, which is **Be(OH)₂**, is amphoteric in character.