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Be forms [BeF(4)]^(2-), but Al forms [Ai...

Be forms `[BeF_(4)]^(2-)`, but `Al` forms `[AiF_(6)]^(3-)`.
Reason (R ): Be does not have `d`-orbitals in the valence shell but `Al` has.

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for statement-1.

B

Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for statement-1.

C

Statement-1 is True, Statement-2 is False.

D

Statement-1 is False, Statement-2 is True.

Text Solution

Verified by Experts

The correct Answer is:
a
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Knowledge Check

  • Nitrogen has no d-orbital in its valence shell and therefore it cannot

    A
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    B
    have covalency greater than 3
    C
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    D
    from oxides with oxidation state greater than +3

  • A : Al forms [Al F_(6)]^(3-) R : It is octahedral complex .

    A
    If both Assertion & Reason are true and the reason is the correct explanation of the assertion , then mark (1)
    B
    If both Assertion & Reason are true but the reason is not the correct explanation of the assertion , then mark (2)
    C
    If Assertion is true statement but Reason is false , then mark (3)
    D
    If both Assertion and Reason are false statements , then mark (4)

  • Aluminum forms [AIF_(6)]^(3-) but boron does not form [BF_(6)]^(3-) because

    A
    The atomic size of B is small
    B
    Of absence of d-orbital in B atom
    C
    Of high I.P B-atom
    D
    B is non -metal

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    Aluminium forms [AIF_(6)]^(3-) ion but boron does not form [BF_(6)]^(3-) ion. Explain.

    Assertion (A) : Al forms [AlF_(6)]^(3-) ions but B does not form [BF_(6)]^(3-) ions. Reason (R) : B does not react with F_(2) .

    Assertion: Al forms [AIF_(6)]^(3-) but B does not from [BF_(6)]^(3-) Reason: BF_(3) on hydrolysis gives HBF_(4) .

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