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A compound (A) of boron reacts with Nme(...

A compound (A) of boron reacts with `Nme_(3)` to give an adduct (B) which on hydrolysis gives a compound (C) and hydrogen gas. Compound (C) is an acid. Identify the compounds A,B and C. give the reactions inovolved.

Text Solution

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Since compound (A) of boron reacts with `Nme_(3)` to form an adduct (B), therefore, (A) must be a Lewis acid.
Since adduct (B) on hydrolysis gives an acid (C ) and hydrogen gas, therefore (A) must be `B_(2)H_(6)` and (C ) must be boric acid.
`underset("Diborane (A)")(B_(2)H_(6)) + underset("Adduct (B)")(2NMe)rarr 2BH_(3).NMe_3, underset((B))(BH_(3).NMe_(3))+3H_(2)O rarr underset("Boric acid (C) ")(H_(3)BO_(3)) + 6H_(2) +NMe_(3)`
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