How does `NaBH_(4)` react with iodine ?

Explanation

To understand how sodium borohydride (NaBH₄) reacts with iodine (I₂), we can break down the reaction step by step.

### Step 1: Identify the Reactants
The reactants in this reaction are sodium borohydride (NaBH₄) and iodine (I₂).

### Step 2: Write the Reaction
When sodium borohydride reacts with iodine, it forms diborane (B₂H₆), sodium iodide (NaI), and hydrogen gas (H₂). The unbalanced reaction can be written as:
\[ \text{NaBH}_4 + \text{I}_2 \rightarrow \text{B}_2\text{H}_6 + \text{NaI} + \text{H}_2 \]
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