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Statement-1. Pb^(4+) compounds are stro...

Statement-1. `Pb^(4+)` compounds are stronger oxidizing agent than `Sn^(4+)` compounds.
Statement-2. The higher oxidation states for the group 14 elements are more stable for the heavier members of the group due to inert pair effect.

A

Statement-1 is True, Statement-2 is True , Statement-2 is a correct explanation for statement-1.

B

Statement-1 is True, Statement-2 is True , Statement-2 is not a correct explanation for statement-1.

C

Statement-1 is True, Statement-2 is False.

D

Statement-1 is False, Statement-2 is True.

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AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will break down each statement and evaluate their validity based on the principles of chemistry, particularly focusing on the group 14 elements. ### Step 1: Analyze Statement-1 **Statement-1:** Pb^(4+) compounds are stronger oxidizing agents than Sn^(4+) compounds. - **Explanation:** Lead (Pb) in the +4 oxidation state is known to be a stronger oxidizing agent compared to tin (Sn) in the +4 oxidation state. This is primarily due to the stability of the oxidation states. Pb^(4+) is less stable than Sn^(4+) because lead is a heavier element and tends to lose its higher oxidation state more readily, thus acting as a stronger oxidizing agent. ### Step 2: Analyze Statement-2 **Statement-2:** The higher oxidation states for the group 14 elements are more stable for the heavier members of the group due to the inert pair effect. - **Explanation:** The inert pair effect refers to the tendency of the s-electrons (the 'inert pair') in the heavier p-block elements to remain non-bonding or less involved in bonding as we move down the group. For heavier elements like lead, the +2 oxidation state is more stable than the +4 oxidation state due to this effect. Therefore, the statement is incorrect as it suggests that higher oxidation states are more stable for heavier elements, which is not true. ### Conclusion - **Statement-1 is True**: Pb^(4+) compounds are stronger oxidizing agents than Sn^(4+) compounds. - **Statement-2 is False**: The higher oxidation states for the group 14 elements are not more stable for the heavier members due to the inert pair effect. ### Final Answer: - Statement-1 is true, and Statement-2 is false.

To analyze the statements provided in the question, we will break down each statement and evaluate their validity based on the principles of chemistry, particularly focusing on the group 14 elements. ### Step 1: Analyze Statement-1 **Statement-1:** Pb^(4+) compounds are stronger oxidizing agents than Sn^(4+) compounds. - **Explanation:** Lead (Pb) in the +4 oxidation state is known to be a stronger oxidizing agent compared to tin (Sn) in the +4 oxidation state. This is primarily due to the stability of the oxidation states. Pb^(4+) is less stable than Sn^(4+) because lead is a heavier element and tends to lose its higher oxidation state more readily, thus acting as a stronger oxidizing agent. ...
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(a) Statement I is true, Satement II is true, Statement II is the correct explanaition of Statement I. (b) Statement I is true, Satement II is true, Statement II is not the correct explanaiton of Statement I. (c ) Statement I is true, Statement II is false (d) Statement I is false : Statement II is true 2. Statement I : Pb^(4+) compounds are stronger oxidising agents than Sn^(2+) compounds . Statement II : The lower oxidation states for the group 14 elements are more stable for the heavier members of the group due to 'inert pair effect'

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