Arrange the following carbanions in order of their decreasing stability. (A) `H_(3)C-C -=C^(-)`
(B) `H-C-=C^(-)` (C) `H_(3)C–CH_(2)^(-)`

Options

A. A gt B gt C
B. B gt A gt C
C. C gt Bgt A
D. C gt A gt B

Answer

B

Explanation

sp-Hybridized carbon is more electronegative than a `sp^3`-hybridized carbon and hence can accommodate the negative charge better. Therefore, (A) and (B) are more stable than (C ). Since `CH_3` group has +I -effect, therefore , it intensifies the negative charge and hence destabilizes A relative to B. Thus, the overall stability decreases in the order : B gt A gt C