The relative reactivity of `1^(@), 2^(@)` and `3^(@)` hybrogen's towards chlorination is `1 : 3.8 : 5`. Calculate the percentages of all monochlorinated products obtained from 2-methylbutane.

Explanation

2-Metylbutane has 4 different sets of equivalent hydrogen atoms marked as 'a', 'b' , 'c' and 'd'
`oversetaCH_3-oversetoverset(.^aCH_3)|(.^bCH)-oversetcCH_2-oversetdCH_3` 2-Methylbutane and hence gives four different types of monochlorinated products . These are :

Relative number of equivalent hydrogens , a:b:c :d =6:1:2:3
Relative amounts of A, B, C and D = No. of hydrogen x relative reactivity
`{:("Relative amounts :",A(1^@),B(3^@), C (2^@),D (1^@)),(,6xx1=6,1xx5=5,2xx3.8=7.6,3xx1=3):}`
Total amount of monohaloginated compounds = 6+5+7.6+3=21.6
% A =`(6xx100)/21.6`=27.72 , %B=`5/21.6xx100`=23.15 , %C=`7.6/21.6xx100=35.22` , %D=`3/21.6xx100=13.85`