Home
Class 12
CHEMISTRY
Two radiations one having red colour ( l...

Two radiations one having red colour `( lambda =7.5 xx10^(-5) cm)`and other with orange colour `( lambda = 6.2 xx 10^(-5) cm)`. Which will have higher energy ?

Text Solution

Verified by Experts

It can be solved as `E= (hc)/(lambda)`
higher is the wavelength of light lesser will be its energy and vice versa `E prop (1)/(lambda)`
Now, the radiation of organge colour has lesser wavelength as compared to red, therefore organge radiation will have higher energy.
Promotional Banner

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    AAKASH INSTITUTE|Exercise Illustration 1|1 Videos

  • STRUCTURE OF ATOM

    AAKASH INSTITUTE|Exercise illustration 2|1 Videos

  • STRUCTURE OF ATOM

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION -D) Assertion-Reason Type Questions|15 Videos

  • SURFACE CHEMISTRY

    AAKASH INSTITUTE|Exercise Assignment Section - C (Assertion - Reason type questions)|10 Videos

Similar Questions

Explore conceptually related problems

Find the ratio of frequency of violet light (lambda_(1) = 4.10 xx %^(-5) cm) to that of red light (lambda_(2) = 6.56 xx 10^(-5) cm) Also determine the ratio of energies carried by them

In Young's experiment, the wavelength of red light is 7.8xx10^(-5) cm and that of blue light is 5.2 xx 10^(-5) cm. The value of n for which (n + 1)th blue light band coincides with nth red band is

In Young's experiment the wavelenght of red light is 7.8xx10^(-5) cm and that of blue light is 5.2xx10^(-5) cm. The value of n for which (n+1)^(th) blue bright band coincides with n^(th) red band is

V_(2) O_(5) is red or orange in colour. It is a//an ….oxide

In Young's experiment the wavelength of red light is 7.5xx10^(-5) cm.and that of blue light 5.0xx10^(-5) .The value of n for which (n+1)^(th) the blue bright band coincides with n^(th) red band is -

Photon having wavelength lambda = 3.5xx10^(-7)m and lambda = 5.4xx10^(-7)m incident on a metal surface successively, let in both cases the ration of their stopping potential is 2 : 1, find work function :

Find energy of photon which have momentum 2 xx10^(-16) gm-cm/sec.

A sample of ._(19)K^(40) disintegrates into two nuclei Ca & Ar with decay constant lambda _(Ca)=4.5 xx10^(-10) S^(-1) and lambda_(Ar)=0.5xx 10^(-10)S^(-1) respectively. The time after which 99% of ._(19)K^(40) gets decayed is