The dissociation constatn of `0.01` M `CH_(3)COOH` is `1.8xx10^(-5)` then calculate `CH_(3)COO^(-)` concentration of 0.1 M HCl solution.

Explanation

`CH_(3)COOHhArrCh_(3)COO^(-)+H^(+)`
`{:(0.01,0,0),(0.01-x,x,x):}`
Here x is very small value.
`K_(a)=([CH_(3)COO^(-)][H^(+)])/([CH_(3)COOH])`
`[CH_(3)COO^(-)]=(1.8xx10^(-5)xx0.01)/(0.1)" "([H^(+)]` is taken from 0.1 MHCl)
`[CH_(3)CCO^(-)]=1.8xx10^(-6)mol//L`