Calculate the pH of 0.10 M solution of `Nh_(4)Cl.` The dissociation constant `(K_(b))` of `NH_(3)` is `1.8xx10^(-5)`

Explanation

To calculate the pH of a 0.10 M solution of NH4Cl, we need to follow these steps:

### Step 1: Identify the nature of NH4Cl
NH4Cl is a salt formed from a strong acid (HCl) and a weak base (NH3). When dissolved in water, it dissociates into NH4+ and Cl- ions. The NH4+ ion can act as a weak acid.

### Step 2: Determine the dissociation constant (Ka) for NH4+
Since NH4+ is the conjugate acid of NH3, we can find its dissociation constant (Ka) using the relationship between Ka and Kb:
\[ K_w = K_a \times K_b \]
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