Calcualte the solubility of `M_(2)X_(3)` in pure water, assuming that neither kind of ion reacts with `H_(2)O`. The solubility product of `M_(2)X_(3), K_(sp) = 1.1 xx 10^(-23)`.

Explanation

`A_(2)X_(3)hArr2A^(+3)+3X^(-2)`
`{:(1,0,0),(1-s,2s,3s):}`
`K_(sp)=[A^(+3)]^(2)[X^(-2)]^(3)`
`(2s)^(2)xx(3s)^(3)`
`=4s^(2)xx27s^(3)`
`=108s^(5)=1.1xx10^(-23)`
`s=((K_(sp))/(108))^(1//5)`
`=((1.1xx10^(-23))/(108))^(1//5)=10^(-5)mol L^(-1)`