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For the reaction, H(2) + I(2)hArr 2HI, K...

For the reaction, `H_(2) + I_(2)hArr 2HI, K = 47.6` . If the initial number of moles of each reactant and product is 1 mole then at equilibrium

A

`[1_(2)]=[H_(2)],[l_(2)]gt[Hl]`

B

`[1_(2)]lt[H_(2)],[l_(2)]=[Hl]`

C

`[1_(2)]=[H_(2)],[l_(2)]lt[Hl]`

D

`[1_(2)]gt[H_(2)],[l_(2)]=[Hl]`

Text Solution

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The correct Answer is:
C
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