Home
Class 12
CHEMISTRY
For a solution if p(A)^(@)=600" mm Hg",p...

For a solution if `p_(A)^(@)=600" mm Hg",p_(B)^(@)=840" mm Hg"` under atmospheric conditions and vapour pressure of solution is 1 atm then find
(i) Composition of solution
(ii) Composition of vapour in equilibrium wiht solution

Text Solution

Verified by Experts

`760=600 x_(A)+840(1-x_(A))`
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    AAKASH INSTITUTE|Exercise ASSIGMENT (SECTION-A)|50 Videos
  • SOLUTIONS

    AAKASH INSTITUTE|Exercise ASSIGMENT (SECTION-B)|21 Videos
  • SOLUTIONS

    AAKASH INSTITUTE|Exercise ASSIGMENT (SECTION-J) AAKASH CHALLENGERS QUESTIONS|10 Videos
  • REDOX REACTIONS

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION - D|10 Videos
  • SOME BASIC CONCEPT OF CHEMISTRY

    AAKASH INSTITUTE|Exercise ASSIGNMENT( SECTION - D) Assertion-Reason Type Questions|15 Videos

Similar Questions

Explore conceptually related problems

Liquids A (p_(A)^(@)=360" mm Hg") and B(p_(B)^(@)=320" mm Hg") are mixed. If solution has vapour has vapour pressure 340 mm Hg, then number of mole fraction of B/mole solution will be

V.P. of solvent in pure state is 600 mm Hg, when a non-volatile solute is added to it vapour pressure of solution becomes 594 mm Hg, then x_(B) will be

The vapour pressure of water is 17.54mm Hg at 293 K. Calculate vapour pressure of 0.5 molal solution of a solute in it.

The vapour pressure of pure benzene at 25^@C is 640 mm Hg and that of the solute A in benzene is 630 mm of Hg. The molality of solution of

The total vapour pressure of equimolar solution of benzene and toluene is given by P_(T) (in mm Hg) =600-400X_("toluene") then:

Vapour pressure of pure A(p_(A)^(@))=100 mm Hg Vapour pressure of pure B(p_(B)^(@))= 150 mm Hg 2 mol of liquid A and 3 mol of liquid B are mixed to form an ideal solution. The vapour pressure of solution will be: