An aqueous solution of glucose is made by dissolving 10 g of glucose in 90 g water at 303 K. If the V.P. of pure water at 303 K be 32.8 mm Hg, what would be V.P. fo the solution ?

Explanation

To find the vapor pressure of the glucose solution, we can use Raoult's Law, which states that the vapor pressure of a solvent in a solution is equal to the vapor pressure of the pure solvent multiplied by its mole fraction in the solution.

### Step-by-Step Solution:

1. **Identify Given Data:**
- Mass of glucose (solute) = 10 g
- Mass of water (solvent) = 90 g
- Vapor pressure of pure water (P₀) = 32.8 mm Hg
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