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Vapour pressure of a solvent decreases b...

Vapour pressure of a solvent decreases by 1% on adding a non-volatile solute `NaSO_(4)`. If it dissociates up to 25% then determine mole-fraction of solute, if solvent is 5 mole.
`(0.01p_(A)^(@))/(p_(A)^(@))=(1.5n_(B))/(n_(B)+n_(A))`

Text Solution

Verified by Experts

`Na_(2)SO_(4) to 2Na^(+)+SO_(4)^(2-)`
Now, `alpha=(i-1)/(m-1)rArr 0.25=(i-1)/(3-1)rArri=1.5`
`:. (0.01P_(A)^(@))/(P_(A)^(@))=iX_(b)`
or `0.01=1.5X_(B)`
or `X_(B)=(1)/(150)`
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