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In 100 g naphthalene 2.56 g sulphur is a...

In 100 g naphthalene 2.56 g sulphur is added boiling point of solution (solid) decreases by `0.68^(@)C`, atomicity of sulphur is
(`K_(f)` of naphthalene=6.8 `Km^(-1)`)

A

2

B

4

C

6

D

8

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4
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A solution containing 25.6 g of sulphur, dissolved in 1000 g of naphthalene whose melting point is 80.1^(@)C gave a freezing point lowering of 0.680^(@)C . Calculate the formula of sulphur ( K_(f) for napthalene = 6.8 K m^(-1) )

When 2.56 g of sulphur is dissolved in 100 g of CS_(2) , the freezing point of the solution gets lowerd by 0.383 K. Calculate the formula of sulphur (S_(x)) . [Given K_(f) for CS_(2)=3.83 "K kg mol"^(-1) ], [Atomic mass of sulphur=32g mol^(-1) ]

In 100g of naphthalene, 2.423g of S was dissolved. Melting point of naphthalene = 80.1^(@)C DeltaT_(f) = 0.661^(@)C. L_(f) = 35.7 cal//g of naphthalene, molecular formula of sulphur is

When 1.2 g of Sulphur is melted with 15 g of naphthalene, the solution freezes at 77.2^(@)C . What is the molar mass of this form of Sulphur? Deta for napthalene: Melting point (f.pt.) 80.0^(@)C Freezing point depression constant K_(f) 6.80Km^(-1)

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