Home
Class 12
CHEMISTRY
A certain mass of substance in 10 g of b...

A certain mass of substance in 10 g of benzene lowers the freezing point by `1.28^(@)C` and in 100 g of water lowers the freezing point by `1.395^(@)C` separately. If the substance has normal molecular weight in benzene and completely dissociated in water, calculate number of moles of ions formed by its 1 mole dissociation in water `(K_(f_("water"))=1.86, K_(f_("benzene"))=5.00)`

Text Solution

Verified by Experts

3
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    AAKASH INSTITUTE|Exercise ASSIGMENT (SECTION-I) SUBJECTIVE TYPE QUESTIONS|10 Videos

  • REDOX REACTIONS

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION - D|10 Videos

  • SOME BASIC CONCEPT OF CHEMISTRY

    AAKASH INSTITUTE|Exercise ASSIGNMENT( SECTION - D) Assertion-Reason Type Questions|15 Videos

Similar Questions

Explore conceptually related problems

A certain mass of a substance when dissolved in 100 g C_(6)H_(6) lowers the freezing point by 1.28^(circ)C . The same mass of solute dissolved in 100 g of water lowers of the freezing point by 1.40^(circ)C . If the substance has normal molecular weight in benzene and is completely dissocited in water, into how many ions does it dissocite in water ? K_(f) for H_(2)O and C _(6)H_(6) are 1.86 and 5.12 K mol^(-1) kg respectively.

6 g of a substance is dissolved in 100 g of water depresses the freezing point by 0.93^(@)C . The molecular mass of the substance will be: ( K_(f) for water = 1.86^(@)C /molal)

0.440 g of a substance dissolved in 22.2 g of benzene lowered the freezing point of benzene by 0.567 ^(@)C . The molecular mass of the substance is _____ (K_(f) = 5.12 K kg mol ^(-1))