In Dumas' method for estimation of nitrogen, `0.3 g` of an organic compound released `50 mL` of nitrgen gas collected under `715 mm Hg` and at `300 K`. If aqueous tension at `300 K` is `15 mm Hg`, calculate the percentage composition of nitrogen in the organic compound.

Explanation

`w=0.30g V_(1)=50ml`
`P_(1)=(P-a)=715-15=700mm` of Hg
`T_(1)=300K`
Now, `(P_(1)V_(1))/(T_(2))=(P_(2)V_(2))/(T_(2))`
`rArr V_(2)=(P_(1)V_(1)xxT_(2))/(T_(1)xxP_(2))=(273xx700xx50)/(300xx760)`
`V_(2)=41.9`ml
Wt. of nitrogen `=(28)/(22400)xx41.9g`
Percentage of Nitrogen `=(28xx41.9)/(22400xx0.3)xx100=17.46`