0.27g of an organic compound gave on combustion 0.396 of `CO_(2)` 0.216g of `H_(2)O` 0.36g of the same substance gave 48.88 ml of `N_(2)` at 290K and 740mm pressure Calculate the percentage composition of the compound.

Explanation

Percentage of `C=(12)/(44)xx(0.396)/(0.27)xx100=40%`
Percentage of `H=(2xx0.216)/(18xx0.27)xx100=8.89%`
w=0.36 g `V_(1)=48.88ml`
`T_(1)=290K P_(1)=740mm`
`P_(2)=760mm T_(2)=273`
`V_(2)=?`
`V_(2)=(P_(1)V_(1)xxT_(2))/(P_(2)T_(1))=(740xx48.88xx273)/(760xx290)=44.80ml`
Percentage of `N=(28)/(22400)xx(44.80)/(0.36)xx100=15.55%`