A body of mass 100 g moving on a test track has final KE of 50 J after traveling a distance of 10 cm. Assuming `90%` loss of energy due to friction, find the intial speed of the body

Explanation

`1/2mv^(2)=50J`
IF initial Ke is `K_(i)thenK_(i)xx10/100=50"Find" K_(i)`
`i_(i)=1/2me^(2)" "m=100/1000kg.` Find u.
`1/2mv^(2)=50J`
Initial `KE=K_(i)`
`K_(i)xx10/100=50`
`K_(i)=500J`
`1/2 m u^(2)=500`
`u=sqrt(((2xx500)/(100))/(1000))=10ms^(-1)`