The velocity (v) of a pariticle of mass m moving along x-axls is given by `v=bsqrtx,` where b is a constant. Find work done by the force acting on the particle during its motion from `x=0` to `x=4m.`

Explanation

`v_(i)=bsqrt0=0`
`v_(f)=bsqrt4=2b`
`W=K_(i)=1/2mv_(f)^(2)-1/2mv_(i)^(2)`
`v_(i)=bsqrt0=0v_(f)=bsqrt4=2b`
`W=K_(f)-K_(i)`
`=1/2mv_(f)^(2)-1/2mv_(1)^(2)`
`=1/2xx m xx4b^(2)`
`=2mb^(2)`