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An engine pumps 800 kg of water through ...

An engine pumps 800 kg of water through height of 10 m in 80 s. Find the power of the engine if its efficiency is `75%`

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`W=mgh" "Pxx75/100=(W)/(Deltat)`
Work done by engine against vgravity
`W=mgh=800xx10xx10=80kJ`
Power used by engine `=(W)/(Deltat)=(80xx10^(3))/(80)W=1kW`
If power of the engine is P,
Then `Pxx75/100=1kW`
`Pxx100/75kW=1.3kW`
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