A 10 metric ton truck drives up a hilly road of gradient 1 in 50 at a speed of `36kmh^(-1)` if the conefficient of kinetic friction between the road and years is 0.2, calculate the power delivered by the engine `(g=10ms^(-2))`

Explanation

To solve the problem, we need to calculate the power delivered by the engine of the truck as it drives up a hilly road. Here are the steps to find the solution:

### Step 1: Convert the speed from km/h to m/s
Given speed = 36 km/h. To convert this to m/s, we use the conversion factor:
\[ 1 \text{ km/h} = \frac{1}{3.6} \text{ m/s} \]
So,
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