For Q. 33, calculate how fast will the same truck move down the hill with same power.

Explanation

Force on the truck when it moves down the hill is
`F'=mgsintheta-mu_(k)mg costheta`
Power, `P=F''v'` calculate v.
Fdorce on the truck when it moves down the hill
`F'=mgsintheta=mu_(k)mgcostheta`
`=mg(sintheta-mu_(k))` (taking ` cos theta=1` as angle is very small)
`=10^(2)((1)/(50)-0.2)`
`=10^(5)((-9)/(50))=-18,000N`
Negative sign signifies direction
Power = F'V'
`22xx10^(4)=18000v`
`v=(220)/(18)=12.5ms^(-1)`
`=12.2xx18/5=43.99`
`=44kmh^(-1)`