Home
Class 12
PHYSICS
A heavy rope is suspended from the ceili...

A heavy rope is suspended from the ceiling of a room. If `phi` is the density of the rope, L be its original length and Y be its. Young's modulus, then increase `DeltaL` in the length of the rope due to its own weight is

A

`DeltaL=(phi gL^(2))/(Y)`

B

`DeltaL=(2phi g L^(2))/(Y)`

C

`DeltaL=(phi g L^(2))/(2Y)`

D

`DeltaL=(phigL)/(Y)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • MECHANICAL PROPERTIES OF SOLIDS

    AAKASH INSTITUTE|Exercise Assignment (SECTION - C)|2 Videos

  • MECHANICAL PROPERTIES OF SOLIDS

    AAKASH INSTITUTE|Exercise Assignment (SECTION - D)|2 Videos

  • MECHANICAL PROPERTIES OF SOLIDS

    AAKASH INSTITUTE|Exercise Assignment (SECTION - A)|31 Videos

  • MECHANICAL PROPERTIES OF FLUIDS

    AAKASH INSTITUTE|Exercise SECTION - J|9 Videos

  • Mock test 03

    AAKASH INSTITUTE|Exercise EXAMPLE|37 Videos

Similar Questions

Explore conceptually related problems

A thick rope of density rho and length L is hung from a rigid support. The increase in length of the rope due to its own weight is ( Y is the Young's modulus)

If the length of a wire is doubled, then its Young's modulus

A copper rod length L and radius r is suspended from the ceiling by one of its ends. What will be elongation of the rod due to its own weight when and Y are the density and Young's modulus of the copper respectively?

A rubber rope of length 8 m is hung from the ceiling of a room. What is the increases in length of the rope due to its own weight? (Given, Young's modulus of elasticity of rubber = 5 xx 10^(6) Nm^(-2) and density of rubber = 1.5 xx 10^(6) kg m^(-3) and g = 10 ms^(-2) )

A wire of length L and radius r suspended from rigid support of mass M gm be applied its free end, its elongation is l , then its Young's modulus is

A copper rod of length l is suspended from the ceiling by one of its ends. Find: (a) the elongation Deltal of the rod due to its own weight , (b) the relative increment of its volume DeltaV//V .

A rubber rope of length 8 m is hung from the ceiling of a room. What is the increase in length of rope due to its own weight? (Given: Young's modulus of elasticity of rubber = 5 xx 10^(6) N//m and density of rubber =1.5xx10^(3)kg//m^(3) . Take g=10ms^(-12))

Increase in length of a wire is 1 mm when suspended by a weight. If the same weight is suspended on a wire of double its length and double its radius, the increase in length will be

A bar of mass m and length l is hanging from point A as shown in the figure . If the Young's modulus of elasticity of the bar is Y and area of cross - section of the wire is A, then the increase in its length due to its own weight will be