Two simple pendulums of lengths 1.44 m a...

Two simple pendulums of lengths 1.44 m and 1 m start swinging together. After how many vibrations will they again start swinging together

5 oscillations of smaller amplitude pendulum

6 oscillations of smaller pendulum

4 oscillations of bigger pendulum

6 oscillations of bigger pendulum

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

OSCILLATIONS
AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION-B )|25 Videos
OSCILLATIONS
AAKASH INSTITUTE|Exercise ASSIGNMENT ( SECTION-C )|11 Videos
OSCILLATIONS
AAKASH INSTITUTE|Exercise Try Yourself|86 Videos
NUCLEI
AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION-D)|10 Videos
PHYSICAL WORLD
AAKASH INSTITUTE|Exercise ASSIGNMENT (Section-B)|5 Videos

Similar Questions

Explore conceptually related problems

Two pendulums of lengths 1.69m and 1.44m start swinging togther. After how many vibrations will they again start swinging togther?

Two simple pendulums of length 100m and 121m start swinging together. They will swing together again after

The pendulums of lengths 100 cm and 110.25 cm start oscillating in phase. After how many oscillation will they again be in same phase ?

Two pendulums of length 90 cm and 100 cm start oscillating in phase. After how many osxillations will they b again in the same phase ?

Two pendulums of lengths 200 cm and 220.50 cm start oscillating in phase. After how many oscillations will they be in same phase for the first time ?

Two simple pendulums of lengths 100 cm and 144cm start oscillating together at time t = 0. The minimum time after which they swing together is (take g=pi^(2)ms^(-2) )

Two simple pendulums of lengths 1.21m and 1.00 m start swinging at the same time from a location. After how much time, they will be (a) out of phase and (b) in phase again? Take g=10m//s^(2) .

Two simple pendulams of lengths 1 and 1.1 m rerspectively start swinging together with the same aplitude. Find the number of swings executed by the longer pendulam before again swing together. [Hint: The longer pendulam will swing more slowely than the shorter. Both will agin begain together after the faster pendulam gains by a complete number of oscillations. Let n be the number of oscillations the longer one makes before they again begain together. therefore (n+x) T_(1)=nT_(2) , where x is the number of oscillations by which the first gains over the second.]

Two simple pendulum A and B of lengths 1.69m and 1.44m start swinging at the time from a location where acceleration due to gravity is 10ms^(-1) . Answer the following question. After how much time, the two pendulums will be in phase again ?

Two simple pendulum A and B of lengths 1.69m and 1.44m start swinging at the time from a location where acceleration due to gravity is 10ms^(-1) . Answer the following question. How many vibratinos pendulum A will compelte when it will be out of phase with B ?

AAKASH INSTITUTE-OSCILLATIONS-ASSIGNMENT ( SECTION -A)

A body of mass 8 kg performs SHM of amplitude 60 cm. The restoring for...
Text Solution
|
A spring of force constant 600 Nm^(-1) is mounted on a horizontal tabl...
Text Solution
|
A spring of force constant 600 Nm^(-1) is mounted on a horizontal tabl...
Text Solution
|
A mass of 1.5 kg is connected to two identical springs each of force c...
Text Solution
|
A mass of 1.5 kg is connected to two identical springs each of force c...
Text Solution
|
A spring of spring constant k is cut in three equal pieces. The spring...
Text Solution
|
Figure-1 to Figure -4 shows four different spring arrangements . Mass ...
Text Solution
|
Two identical springs have the same force constant of 147Nm^(-1). What...
Text Solution
|
The frequency of oscillation of amass m suspended by a spring is v(1)....
Text Solution
|
The total energy of a simple pendulum is x. When the displacement is ...
Text Solution
|
The acceleration of a body in SHM is
Text Solution
|
In SHM, the plot of acceleration y at time t and displacement x for on...
Text Solution
|
A uniform rod ofmass M and length L is hanging from its one end fre...
Text Solution
|
An ideal liquid having length of liquid column l is column in V-shape...
Text Solution
|
In the arrangement shown in figure a solid sphere is attached to sprin...
Text Solution
|
In previous problem ( i.e., Question) ,if lift is moving downward with...
Text Solution
|
A disc is hanging from pin hole as shown in figure and displaced sligh...
Text Solution
|
A point mass m is suspended at the end of a massless wire of length l ...
Text Solution
|
A heavy brass sphere is hung froma weightless inelastic string and use...
Text Solution
|
Two simple pendulums of lengths 1.44 m and 1 m start swinging together...
Text Solution
|