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Two spheres made of same substance have ...

Two spheres made of same substance have diameters in the ratio 1:2. their thermal capacities are in the ratio of

A

`1:2`

B

`1:8`

C

`1:4`

D

`2:1`

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To find the ratio of thermal capacities of two spheres made of the same substance with diameters in the ratio of 1:2, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between diameter and radius**: - Let the diameter of the first sphere be \( d_1 \) and the second sphere be \( d_2 \). - Given the ratio \( \frac{d_1}{d_2} = \frac{1}{2} \). - Therefore, the radii \( r_1 \) and \( r_2 \) can be expressed as: \[ r_1 = \frac{d_1}{2}, \quad r_2 = \frac{d_2}{2} = \frac{1}{2} \cdot \frac{d_2}{2} = \frac{1}{2} \cdot 1 = 1 \] - Thus, \( \frac{r_1}{r_2} = \frac{1}{2} \). 2. **Calculate the volumes of the spheres**: - The volume \( V \) of a sphere is given by the formula: \[ V = \frac{4}{3} \pi r^3 \] - For the first sphere: \[ V_1 = \frac{4}{3} \pi r_1^3 \] - For the second sphere: \[ V_2 = \frac{4}{3} \pi r_2^3 \] 3. **Express the volumes in terms of the radius ratio**: - Since \( r_1 = \frac{1}{2} r_2 \), we can express \( V_1 \) in terms of \( V_2 \): \[ V_1 = \frac{4}{3} \pi \left(\frac{1}{2} r_2\right)^3 = \frac{4}{3} \pi \cdot \frac{1}{8} r_2^3 = \frac{1}{6} \cdot \frac{4}{3} \pi r_2^3 = \frac{1}{6} V_2 \] 4. **Calculate the thermal capacities**: - The thermal capacity \( C \) of a substance is given by: \[ C = m \cdot c \] where \( m \) is the mass and \( c \) is the specific heat capacity. - The mass \( m \) of the sphere can be expressed as: \[ m = \rho V \] where \( \rho \) is the density of the material. - Therefore, the thermal capacities for both spheres can be written as: \[ C_1 = \rho V_1 c, \quad C_2 = \rho V_2 c \] 5. **Find the ratio of thermal capacities**: - The ratio of thermal capacities \( \frac{C_1}{C_2} \) becomes: \[ \frac{C_1}{C_2} = \frac{\rho V_1 c}{\rho V_2 c} = \frac{V_1}{V_2} \] - Substituting the volume ratio: \[ \frac{C_1}{C_2} = \frac{\frac{1}{6} V_2}{V_2} = \frac{1}{6} \] 6. **Final Ratio**: - Thus, the ratio of their thermal capacities is: \[ \frac{C_1}{C_2} = \frac{1}{6} \] ### Conclusion: The thermal capacities of the two spheres are in the ratio of \( 1:6 \).
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