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In the given circuit a silicon diode wit...

In the given circuit a silicon diode with knee voltage 0.7V is forward biased with a battery of e.m.f 8V. The current in the circuit is 40 mA. Find the power drop at resistor R and diode.

Text Solution

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Here e.m.f of battery =8V
Knee voltage `V_("Knee")=0.7V`
Voltage drop across R is =8-0.7 =7.3 V
Current in the circuit I=4.0 mA
`=40xx10^(-3) A`
Power drop at resistor R=Voltage drop across R x current
`=7.3xx40xx10^(-3)`
`=29.2xx10^(-2)W`
Power drop at diode =voltage drop across diode x current
`=0.7xx40xx10^(-3)`
`=28xx10^(-3) W`
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