Solve for x, `tan^(-1)2x+tan^(-1)3x=pi/4`

Explanation

To solve the equation \( \tan^{-1}(2x) + \tan^{-1}(3x) = \frac{\pi}{4} \), we can follow these steps:

### Step 1: Apply the tangent function to both sides
Since \( \tan^{-1}(a) + \tan^{-1}(b) = \frac{\pi}{4} \), we can take the tangent of both sides:
\[ \tan\left(\tan^{-1}(2x) + \tan^{-1}(3x)\right) = \tan\left(\frac{\pi}{4}\right) \]
This simplifies to:
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