If 0 < x <1, then sqrt(1+x^2)[{xcos(cot^...

If `0 < x <1,` then `sqrt(1+x^2)[{xcos(cot^-1x)+sin(cot^-1 x)}^2-1]^(1/2)` is equal to

`x/sqrt(1=x^2)`

`xsqrt(1+x^2)`

`sqrt(1+x^2)`

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

INVERSE TRIGONOMETRIC FUNCTIONS
AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION - B)(OBJECTIVE TYPE QUESTIONS (ONE OPTION IS CORRECT))|36 Videos
INVERSE TRIGONOMETRIC FUNCTIONS
AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION - C)(OBJECTIVE TYPE QUESTIONS (MORE THAN ONE OPTIONS ARE CORRECT))|13 Videos
INVERSE TRIGONOMETRIC FUNCTIONS
AAKASH INSTITUTE|Exercise TRY YOURSELF|21 Videos
INTEGRALS
AAKASH INSTITUTE|Exercise Try yourself|50 Videos
LIMITS AND DERIVATIVES
AAKASH INSTITUTE|Exercise Section - j|3 Videos

Similar Questions

Explore conceptually related problems

If A = [{:( 0,0,0),(0,0,0) ,(0,1,0):}] ,then A is

If A = [{:( 0,0,0),( 1,0,0),(0,1,0):}] ,then

If A =[{:(a,0,0),(0,a,0),(0,0,a):}] , then det (adjA) equals

If A = [(3,0,0),(0,3,0),(0,0,3)] , then |A||adj A| =...

If A = {:[(2,0,0),(0,2,0),(0,0,2)]:}, then A^(6) = .........

If A =[{:(2,0,0),(0,1,0),(0,0,1):}] then adj(A) =

If x, y, z are non-zero real numbers, then the inverse of matrix A=[(x,0, 0) ,(0,y,0),( 0, 0,z)] is (A) [[x^(-1),0,0],[0,y^(-1),0],[0,0,z^(-1)]] (B) xyz[[x^(-1),0,0],[0,y^(-1),0],[0,0,z^(-1)]] (C) (1)/(xyz)[[x,0,0],[0,y,0],[0,0,z]]] (D) (1)/(xyz)[[1,0,0],[0,1,0],[0,0,1]]

If x ,\ y ,\ z are non-zero real numbers, then the inverse of the matrix A=[x0 0 0y0 0 0z] , is [x^(-1)0 0 0y^(-1)0 0 0z^(-1)] (b) x y z[x^(-1)0 0 0y^(-1)0 0 0z^(-1)] (c) 1/(x y z)[x0 0 0y0 0 0z] (d) 1/(x y z)[1 0 0 0 1 0 0 0 1]

Choose the correct answer in questions 17 to 19: If x, y, z are nonzero real numbers then the inverse of metrix A=[{:(x,0,0),(0,y,0),(0,0,z):}] is : (a) [{:(x^(-1),0,0),(0,y^(1),0),(0,0,z^(1)):}] (b) xyz[{:(x^(-1),0,0),(0,y^(1),0),(0,0,z^(1)):}] ( c) 1/(xyz)[{:(x,0,0),(0,y,0),(0,0,z):}] (d) 1/(xyz)[{:(1,0,0),(0,1,0),(0,0,1):}]

AAKASH INSTITUTE-INVERSE TRIGONOMETRIC FUNCTIONS-ASSIGNMENT (SECTION - A)(OBJECTIVE TYPE QUESTIONS (ONE OPTION IS CORRECT))

If sin^(-1)(x-x^2/2+x^3/4…..oo)+cos^(-1)(x^2-x^4/2+x^6/4-……oo)=pi/2 th...
Text Solution
|
if tan^(-1)(1/x)+cos^(-1)(2/sqrt5)=pi/4 then x equals
Text Solution
|
If 0 < x <1, then sqrt(1+x^2)[{xcos(cot^-1x)+sin(cot^-1 x)}^2-1]^(1/2)...
Text Solution
|
If x1=cos^(-1)(3/5)+cos^(-1)((2sqrt2)/3)and x2=sin^(-1)(3/5)+sin^(-1)(...
Text Solution
|
If tan(sin^(-1)sqrt(1-x^2))=sin(tan^(-1)2) then x is
Text Solution
|
If 0 le x le 1 then cos^(-1)(2x^(2)-1) equals
Text Solution
|
Express in terms of : sin^(-1)(2xsqrt(1-x^(2))) to sin^(-1)x for 1gexg...
Text Solution
|
sin^(-1) (5/x) +sin^(-1) (12/x) =pi/2
Text Solution
|
tan^(-1)((sqrt(1+x^2)+sqrt(1-x^2))/(sqrt(1+x^2)-sqrt(1-x^2))),absxx le...
Text Solution
|
If cos^(-1)(x/m)+cos^(-1)(y/n)=theta, then x^2/m^2-(2xy)/(mn)costheta+...
Text Solution
|
tan^(-1)(1/2)+tan^(-1)(1/3) is equal to
Text Solution
|
cos(tan^(-1)3/4)+cos(tan^(-1)x) is equal to
Text Solution
|
If cot^(-1)x+tan^(-1)(1/2)=pi/4 then x is
Text Solution
|
The value of cos^(-1)(-1)+sin^(-1)(1) is
Text Solution
|
If sin^(- 1)(3/x)+sin^(- 1)(4/x)=pi/2 then x=
Text Solution
|
The domain of the function f(x)=cos^(-1)((2-absx)/4) is
Text Solution
|
The domain of the function given by f(x)=sqrt(sin^(-1)(2x)+pi/6) is
Text Solution
|
tan^(-1)x-tan^(-1)y=tan^(-1)((x-y)/(1+xy)) holds good for
Text Solution
|
If sin^(-1)x+sin^(-1)(1-x)+cos^(-1)x=0, then x is
Text Solution
|
sin^(-1)(sinx)=x if
Text Solution
|