Home
Class 12
MATHS
STATEMENT-1 : The solution of sin^-1 6x...

STATEMENT-1 : The solution of `sin^-1 6x+sin^-1 6sqrt3x=pi/2` is , `x= +- 1/12.` and STATEMENT - 2 As, `sin^-1 x` is defined for `|x| <= 1.`

A

Statement -1 is True, Statement-2 is True, Statement -2 is a correct explanation for Statement -5

B

Statement -1 is True, Statement -2 is True, Statement -2 is NOT a correct explanation for Statement -5

C

Statement-1 is True, Statement -2 is False

D

Statement -1 is False, Statement -2 is True

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • INVERSE TRIGONOMETRIC FUNCTIONS

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION - G)(INTEGER ANSWER TYPE QUESTIONS)|3 Videos

  • INVERSE TRIGONOMETRIC FUNCTIONS

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION - H)(MULTIPLE TRUE-FALSE TYPE QUESTIONS)|1 Videos

  • INVERSE TRIGONOMETRIC FUNCTIONS

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION - D)(LINKED COMPREHENSION TYPE QUESTIONS)|9 Videos

  • INTEGRALS

    AAKASH INSTITUTE|Exercise Try yourself|50 Videos

  • LIMITS AND DERIVATIVES

    AAKASH INSTITUTE|Exercise Section - j|3 Videos

Similar Questions

Explore conceptually related problems

STATEMENT-1: The solution of sin^(-1)6x+sin^(-1)6sqrt(3)x=(pi)/(2) is x=+-(1)/(12) .and STATEMENT -2 As,sin^(-1)x is defined for |x|<=1

Solve: sin^(-1)6x + sin^(-1)6 sqrt3x =-pi/2 .

The solution of sqrt(5-2sin x)>=6sin x-1 is

Solve the equation sin^(-1)6x+sin^(-1)6sqrt(3)x=(-pi)/(2)

The solution of sin^(-1)|sin x|=sqrt(sin^(-1)|sin x|) is

Solve: sin^(-1)x + sin^(-1)2x = pi/3 .

Solve sin^(-1)x+sin^(-1)2x=(pi)/(3)

Solve sin^(-1)x + sin^(-1) 2x = (pi)/(3)