Find the Cartesian from the equation of the plane
`vecr=(s-2t)hati+(3-t)hatj+(2s+t)hatk`.

Explanation

We have,
`vecr=(s-2t)hati+(3-t)hatj+(2s+t)hatk`
`ltimplies (xhati+yhatj+zhatk)=(s-2t)hati+(3-t)hatj+(2s+t)hatk`
`ltimplies x-2y+6=1/2(y+z-3)` [equating the values of x]
`ltimplies 2x-4y+12=y+z-3 rArr 2x-5y-z+15=0`.
This is the required Cartesian form of the equation of the given plane.