Find the vector equation of plane which is paralel to the plane `vecr.(2hati-3hatj+5hatk)+2=0` and passes through the point (3,4,-1).

Explanation

Any plane parallel to the plane `ver.(2hati-3hatj+5hatk)+2=0` is given by `vecr.(2hati-3hatj+5hatk)=q` for some constant q………(i)
Since, it passes through a point `A(3,4,-1)` whose position vector is `(3hati+4hatj-hatk)` we have.
`(3hati+4hatj-hatk).(2hati-3hatj+5hatk=q rArr q=(6-12-5)=-11`.
Putting `q=-11` in (i), we get the the required of the plane is as
`vecr.(2hati-3hatj+5hatk)=-11 rArr vecr.(2hati-3hatj+5hatk)+11=0`.