Find the equation of the plane passing through the point (1,3,2) and parallel to the plane is `3x-2y+2z+33=0`.

Explanation

The equation of a plane parallel to the given plane is of the form
`3x-2y+2z=`k for some scalar k. …………(i)
Since it passes through the point A(1,3,2), we have
`(3 xx 1) -(2 xx 3)+(2 xx 2)=k rArr k=(3-6+4)=1`.
Hence, the required equation of the plane is
`3x-2y+2z-1=0`.