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Reduce the equation of the plane 4x-3y+2...

Reduce the equation of the plane `4x-3y+2z=12` to the intercept form, and hence find the intercepts made by the plane with the coordinate axes.

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The correct Answer is:
`x/3+y/-4+z/6=1`, Intercepts on the axes are `3,-4,6`.
`4x-3y+2z=12 rArr x/3+y/-4+z/6=1` [on dividing each term by 12].
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