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The line (x-4)/1=(y-2)/1=(z-k)/2 lies ex...

The line `(x-4)/1=(y-2)/1=(z-k)/2` lies exactly on the plane `2x=4y+z=7` then the value of k is (A) 7 (B) -7 (C) 1 (D) none of these

A

`-7`

B

7

C

4

D

`-4`

Text Solution

Verified by Experts

The correct Answer is:
b
Clearly, the given line passes through the point (4,2,k).
Since, the given line lies in the plane `2x-4y+z=7`, so the above point lies in this plane.
`therefore (2xx4)-(4 xx 2)+k=7 rArr k=7`.
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