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There are 15 couples taking part in a si...

There are 15 couples taking part in a single tournament , the number of ways in which they can be paired such that no two real lives couple play in the same team is

A

`15!(1-(1)/(1!)+(1)/(2!)-(1)/(3!)* * * * * * -(1)/(15!))`

B

`15!`

C

`""^(30)C_(2)`

D

`""^(30)C_(2)-""^(15)C_(1)`

Text Solution

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The correct Answer is:
A
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