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sum(r=0)^(m) ""^(n+r)C(n) is equal to...

`sum_(r=0)^(m) ""^(n+r)C_(n)` is equal to

A

`""^(n+m+1)C_(n+1)`

B

`""^(n+m+""^(2)C_(n)`

C

`""^(n+m+1)C_(m)`

D

`""^(n+m-1)C_(m-1)`

Text Solution

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The correct Answer is:
A, C
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