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If delta =|(a1,b1,c1),(a2,b2,c2),(a3,b3,...

If `delta =|(a_1,b_1,c_1),(a_2,b_2,c_2),(a_3,b_3,c_3)|` then the value of `|(2a_1+3b_1+4c_1,b_1,c_1),(2a2+3b_2+4c_2,b_2,c_2),(2a_3+3b_3+4c_3,b_3,c_3)|` is equal to

A

`Delta^2`

B

`4Delta`

C

`Delta`

D

`2Delta`

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The correct Answer is:
D
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