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underset(x to 2)(Lt) {[x - 2] + [2 - x] ...

`underset(x to 2)(Lt) {[x - 2] + [2 - x] - x} =` where [.] represents greater intergral function

A

0

B

3

C

`-3`

D

`-2`

Text Solution

Verified by Experts

The correct Answer is:
C
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