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KHF(2) exists while KHCl(2) does not. Ex...

`KHF_(2)` exists while `KHCl_(2)` does not. Explain.

Text Solution

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Due to H-bonding in HF, we have
`H-F----H-F----H-F----`
This can dissociate to give `HF_(2)^(-)` ion and hence `KHF_(2)` exists but there is no H-bonding in H-Cl. So `Hcl_(2)^(-)`
ion does not exist and hence `KHCl_(2)` also does not exist
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