In both water and diethyl ether, the central atom viz. O-atoms has same hybridisation . Then why have they different bond angles ? Which one has greater bond angle ?

Explanation

The central atom in each case is `sp^(3)` hybridized . Hence , expected
bond angle in each sase is `109^(@)28`' . The two pairs present on
O-atom repel the bond pairs and hence tend to reduce the bond
angle . However, the greater repulsions between two ethyi groups,
in diethyi ether than between the two H-atoms in `H_(2)O` result in
greater bond angle `(110^(2))` in diethyi ether than that in `H_(2)O`
`(104.5^(@))` .