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In [Ag(CN)2]^(-), the number of pi bonds...

In `[Ag(CN)_2]^(-)`, the number of `pi` bonds is

A

2

B

3

C

4

D

6

Text Solution

Verified by Experts

The correct Answer is:
C
`[N-=C-Ag-C-=N]^(-)`
Thus , number of `pi` bonds = 4 .
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