Consider the following molecules or ions :
(i) `CH_(2) Cl_(2) (ii) NH_(4)^(+) (iii) SO_(4)^(2-) (iv) ClO_(4)^(-) (v) NH_(3)`
`sp^(3)` hybridisation is involved in the formation of

Options

A. (i), (ii), (v) only
B. (i) , (ii) only s
C. (ii) only
D. (i), (ii), (iii), (iv) and (v)`

Explanation

To determine which of the given molecules or ions exhibit `sp^3` hybridization, we will analyze each one based on the number of sigma bonds and lone pairs around the central atom. The `sp^3` hybridization occurs when the steric number (the sum of sigma bonds and lone pairs) is 4.

### Step-by-Step Solution:

1. **Analyze CH₂Cl₂ (Dichloromethane)**:
- Central atom: Carbon (C)
- Bonds: 2 Hydrogen (H) atoms and 2 Chlorine (Cl) atoms are bonded to Carbon.
- Total sigma bonds: 4 (2 C-H + 2 C-Cl)
...