The percentage of p-character in `SF_(6)` are

Options

A. `120^(@), 20%`
B. `90^(@), 33%`
C. `109^(@), 25%`
D. ` 90^(@), 25%`

Explanation

To find the percentage of p-character in SF₆ (sulfur hexafluoride), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Hybridization of SF₆**:
- SF₆ has a central sulfur atom surrounded by six fluorine atoms. The hybridization of sulfur in SF₆ is sp³d².

2. **Determine the Orbitals Involved in Hybridization**:
- In sp³d² hybridization, the orbitals involved are:
- 1 s-orbital
- 3 p-orbitals
- 2 d-orbitals
- Therefore, the total number of orbitals involved is:
\[ 1 \text{ (s)} + 3 \text{ (p)} + 2 \text{ (d)} = 6 \text{ orbitals} \]

3. **Calculate the Percentage of p-character**:
- The percentage of p-character can be calculated using the formula:
\[ \text{Percentage of p-character} = \left( \frac{\text{Number of p-orbitals}}{\text{Total number of orbitals}} \right) \times 100 \]
- Substituting the values:
\[ \text{Percentage of p-character} = \left( \frac{3}{6} \right) \times 100 = 50\% \]

### Final Answer:
The percentage of p-character in SF₆ is **50%**.

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