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Out of N(2) O , SO(2), I(3)^(+), I(3)^(...

Out of `N_(2) O , SO_(2), I_(3)^(+), I_(3)^(-), H_(2)O, NO_(2)^(-) and N_(3)^(-)`
the linear species are

A

`NO_(2)^(-), I_(3)^(+), H_(2)O`

B

`N_(2)O,I_(3)^(-), N_(3)^(-)`

C

`N_(2)O, I_(3)^(-), N_(3)^(-)`

D

`N^(3-),I_(3)^(+), SO_(2)`

Text Solution

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The correct Answer is:
To determine which of the given species are linear, we will analyze each compound using the concept of steric number and molecular geometry. ### Step 1: Understand the concept of steric number The steric number is calculated using the formula: \[ \text{Steric Number} = \frac{( \text{Number of valence electrons of central atom} + \text{Number of monovalent atoms} - \text{Charge})}{2} \] A linear molecular geometry typically corresponds to a steric number of 2 or 5. ### Step 2: Analyze each compound 1. **N₂O (Nitrous oxide)** - Valence electrons: N (5) + N (5) + O (6) = 16 - Central atom: N (one of the nitrogen atoms) - Bonds: 3 (N≡N and N=O) - Lone pairs on central N: 1 - Steric number = (5 + 0 - 0)/2 = 2.5 (not linear) 2. **SO₂ (Sulfur dioxide)** - Valence electrons: S (6) + O (6) + O (6) = 18 - Central atom: S - Bonds: 2 (S=O) and 1 lone pair - Steric number = (6 + 0 - 0)/2 = 3 (not linear) 3. **I₃⁺ (Triiodide cation)** - Valence electrons: I (7) + I (7) + I (7) - 1 (positive charge) = 20 - Central atom: I - Bonds: 2 (I-I) and 2 lone pairs - Steric number = (7 + 2 - 1)/2 = 4 (not linear) 4. **I₃⁻ (Triiodide anion)** - Valence electrons: I (7) + I (7) + I (7) + 1 (negative charge) = 21 - Central atom: I - Bonds: 2 (I-I) and 3 lone pairs - Steric number = (7 + 2 + 1)/2 = 5 (linear) 5. **H₂O (Water)** - Valence electrons: H (1) + H (1) + O (6) = 8 - Central atom: O - Bonds: 2 (O-H) and 2 lone pairs - Steric number = (6 + 0 - 0)/2 = 4 (not linear) 6. **NO₂⁻ (Nitrite ion)** - Valence electrons: N (5) + O (6) + O (6) + 1 (negative charge) = 18 - Central atom: N - Bonds: 2 (N=O) and 1 lone pair - Steric number = (5 + 0 + 1)/2 = 3 (not linear) 7. **N₃⁻ (Azide ion)** - Valence electrons: N (5) + N (5) + N (5) + 1 (negative charge) = 16 - Central atom: N (central nitrogen) - Bonds: 2 (N≡N) and 1 lone pair - Steric number = (5 + 0 + 1)/2 = 3 (not linear) ### Step 3: Conclusion The only linear species from the list is **I₃⁻ (Triiodide anion)**. ### Summary of Linear Species: - **Linear Species**: I₃⁻

To determine which of the given species are linear, we will analyze each compound using the concept of steric number and molecular geometry. ### Step 1: Understand the concept of steric number The steric number is calculated using the formula: \[ \text{Steric Number} = \frac{( \text{Number of valence electrons of central atom} + \text{Number of monovalent atoms} - \text{Charge})}{2} \] A linear molecular geometry typically corresponds to a steric number of 2 or 5. ### Step 2: Analyze each compound ...
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