The correct order of bond order values among the following
(i) `NO^(-)` (ii) `NO^(+)`
(iii) `NO` (iv) `NO^(2+)`
(v) `NO^(2-)`

Options

A. `A lt D lt C lt B lt E`
B. `D = B lt A lt E le C `
C. `E lt A lt D = C lt B`
D. `B lt C lt D lt A lt E `

Answer

C

Explanation

`NO=KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(2)pi_(2p_(x))^(**1)`
B.O. `= (1)/(2) (8-3) = (5)/(2) = 2.5 `
`NO^(-)=KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(2)pi_(2p_(x))^(**1)pi_(2p_(y))^(**1)`
B.O. = `(1)/(2) (8-4)= 2`
`NO^(2-)=KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(2)pi_(2p_(x))^(**2)pi_(2p_(y))^(**1)`
B.O. = `(1)/(2) (8-5) = (3)/(2) = 1.5 `
`NO^(+)=KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(x))^(2)pi_(2p_(y))^(2)`
B.O. `= (1)/(2) (8-2) = 3 `
`NO^(2+)=KK sigma_(2)^(2) sigma_(2s)^(**2) sigma_(2p_(z))^(2) pi_(2p_(x))^(2)pi_(2p_(y))^(1)`
B.O. ` = (1)/(2) (7-2) = (5)/(2) = 2.5 `
Thus `NO^(2-) lt NO^(-) NO = NO^(2-) lt NO^(+)`,
i.e. `E lt A lt C = D lt B `