Arrange the following ions in the order of decreasing `X-O` bond length where X is the central atom:

Options

A. `ClO_(4)^(-_ , SO_(4)^(2-), PO_(4)^(3-), SiO_(4)^(4-)`
B. `SiO_(4)^(4-) ,PO_(4)^(3-) , SO_(4)^(2-) , ClO_(4)^(-)`
C. `SiO_(4)^(4-) , PO_(4)^(3-), ClO_(4)^(-) , SO_(4)^(2-)`
D. `SiO_(4)^(2-), SO_(4)^(2-) , PO_(4)^(3-) , ClO_(4) ^(-)`

Answer

B

Explanation

Greater the bond order , shorter is the bond length.
Hence X-O bond lengths will be in the order :
`SiO_(4)^(4-) gt PO_(4)^(3-)gt SO_(4)^(2-) gt ClO_(4)^(-)`