Among `KO_(2), KAlO_(2), CaO_(2) and NO_(2)^(+)`, unpaired electrons is present in :

Options

A. `NO_(2)^(+) and BaO_(2)`
B. `KO_(2) and AlO_(2)^(-)`
C. `KO_(2)` only
D. `BaO_(2)` only

Answer

C

Explanation

Electrons present :
`NO_(2)^(+) = 7 + 16 - 1 = 22 , BaO_(2) = 56 + 16 = 72 `
`AlO_(2)^(-) = 13 + 16 + 1 = 30 `
and `KO_(2) = 19 + 16 = 35`
Thus , olny `KO_(2)` is odd electron species.