`0.5 mol` of `H_(2)`, `SO_(2)`, and `CH_(4)` is kept in a container. A hole was made in the container. After `3 hours`, the order of partial pressure in the container will be

Options

A. `p_(SO_(2)) gt p_(CH_(4)) gt p_(H_(2))`
B. `p_(H_(2)) gt p_(SO_(2)) gt p_(CH_(4))`
C. `p_(H_(2)) gt p_(SO_(2)) gt p_(CH_(4))`
D. `p_(H_(2)) gt p_(CH_(4)) gt p_(SO_(2))`

Answer

A

Explanation

Equal moles of three gases means equal partial pressures in the beginning. As rate of diffusion
`prop sqrt((1)/("Mol mass"))`, therefore, rates of diffusion will he in the order : `H_(2) gt CH_(4) gt SO_(2)`. Hence, amounts left will be in the order `H_(2) lt CH_(4) lt SO_(2)` or `SO_(2) gt CH_(4) gt H_(2)`. Their partial pressures will also be in the same order.